v=∫dv where lim->r, lim->(-r)
v= π∫(r^2-x^2)dx, which again means that v= π(∫r^2dx - ∫x^2dx) where lim->r, lim->(-r)
v=πr^2∫dx - π∫x^2dx
v=πr^2[x](lim->r and -r)-π[1/3x^3](lim->r, lim->(-r)
v=πr^2(r+r)-((π/3)(r^3+r^3))
v=2πr^3-((2π/3)(r^3)) = ((6πr/3)(r^3))-((2π/3)(r^3))
v=((4π/3)(r^3)) which is the final answer
How about that faggots.